1.

How many alpha and beta -particles are emitted whenU^(238) changes to Pb^(206) due to radioactivity? Atomic number of U^(238) changes to Pb^(206) are 92 and 82 respectively.

Answer»

Solution :Let, x = number of `ALPHA`-particles emitted
`""`y = number of `beta`-particles emitted
DECREASE in MASS number = 4x
Decrease in atomic number = (2x -y)
Here, 4x = 238 - 206 = 32or, x = 8
And, 2x - y = 92 - 82 = 10
or,y = 2x -10 = 2 `xx` 8 - 10 = 6


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