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How many atoms and molecules of sulphur are present in 64.0 g of sulphur (S_(8))? |
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Answer» SOLUTION :Molecular formula of sulphur = `S_(8)` `therefore"Molecular mass of sulphur "(S_(8))=32xx8=256.0u` 1 MOLE of sulphur molecules = 256 g = `6.022xx10^(23)` molecules of sulphur Now, 256 g of sulphur contain `6.022xx10^(23)" molecules"` `therefore"64 g of sulphur will contain"=(6.022xx10^(23)xx64)/(256)=1.506xx10^(23)" molecules."` 1 molecule of sulphur `(S_(8))` contains 8 ATOMS of sulphur `therefore 1.506xx10^(23)` molecule of sulphur will contain sulphur atoms = `8xx1.506xx10^(23)=1.2048xx10^(24)` atoms. |
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