1.

How many coulombs are required to produce 40.5 g of Al from molten Al_(2)O_(3)?

Answer»

Solution :`Al_(2)O_(3)hArr2Al^(3+)+3O^(2-)`
`Al^(3)+3etoAl`
`27g.3F`
27 G of Al is produced from ELECTRICITY `=3xxF`
40.5 g of Al will be produced from electricity
`=(3F)/(27)xx40.5`
=4.5 F
`=4.5xx96500`
=434250 C


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