How many degrees of freedom have the gas molecules, if under standard conditions the gas density is `1.3 kg m^(-3)` and the velocity of sound propagation in it is `C=330 m s^(-1)`.A. 5B. 6C. 7D. 8

How many degrees of freedom have the gas molecules, if under standard

1.	How many degrees of freedom have the gas molecules, if under standard conditions the gas density is `1.3 kg m^(-3)` and the velocity of sound propagation in it is `C=330 m s^(-1)`.A. 5B. 6C. 7D. 8
Answer» Correct Answer - A We know that, `v=sqrt((gammap)/(p))` `gamma=(v^(2)p)/(p)=((330)^(2)xx1.3)/(1.015xx10^(5))=1.4` `rArr" "1+1/n=1.4rArrn=5`

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How many degrees of freedom have the gas molecules, if under standard conditions the gas density is `1.3 kg m^(-3)` and the velocity of sound propagation in it is `C=330 m s^(-1)`.A. 5B. 6C. 7D. 8

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