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How many electrons are lost and gained by 2 g of Cl^(-) ions and 1 g of Zn^(2+) ions as the result of electrolysis respectively ?(Cl = 35.5, Zn = 65) |
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Answer» Solution :Number of equivalents of `Cl^(-)` ions `= ("weight")/("eq. wt.")` `= (2)/(35.5)` Number of equivalent of `Zn^(2+)` ions `= (1)/(65//2) = (2)/(65)`. Now,1 MOLE (1F) of electric charge discharges 1 equivalent of matter. MOLAR of electric charge involved in CASE of `Cl^(-) = (2)/(35.5)` Mole of electric charge involved in case of `Zn^(2+) = (2)/(65)`. As 1 mole of electric charge corresponds to AV. no. of electrons, thus, no. of electrons lost by `Cl^(-) = (2)/(35.5) xx 6.022 xx 10^(23)` and no. of electrons gained by `Zn^(2+) = (2)/(65) xx 6.022 xx 10^(23)`. |
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