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How many electrons flow through a metallic wire if a current of 0.5 A is passed for 2 hours? (Given 1F=96,500 C mol^(-1))

Answer»

Solution :Charge flowing through the METALLIC wire`=Ixxt=0.5xx2xx60xx60C=3600C`
But charge flowing=no. of electrons flowing `XX`charge on each ELECTRON
`therefore3600=nxx1.60xx10^(-19)`
or `n=(3600)/(1.60xx10^(-19))=2.25xx10^(22)`.


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