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How many electrons flow when a current of 5 amperes is passed through a solution for 193 seconds ? |
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Answer» Quantity of charge passed (Q)`=(5 amp)xx(193 s)=965 C` By PASSING 96500 C (1F) of charge, the electrons flowing `=6.022xx10^(23)` By passing 965 C of charge, the electrons flowing `=(6.022xx10^(23))/((96500C))xx(965C)=6.022xx10^(21)` |
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