1.

How many electrons per second pass through a cross-section od a copper wire carrying 10^(-5)A ? (charge of 1 electron is 1.0 xx 10^(-19) coulomb ).

Answer»

`1.6 xx 10^(-36)`
`1 xx 10^(+14)`
6250
62500

Solution :96,500 C=1 mole of `E^(-) =6.023 xx 10^(23)`
`therefore` Number of ELECTRONS PASSING through wire of `10^(-5)` C=`(10^(-5)xx6.023xx10^(23))/(96,500)`


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