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How many empty orbitals are available in the central metal ion of a complex that has a trigonal bipyramidal geometry?(a) 2(b) 3(c) 4(d) 5I had been asked this question during an online exam.My enquiry is from Bonding in Coordination Compounds topic in portion Coordination Compounds of Chemistry – Class 12

Answer»

The correct choice is (d) 5

The explanation: One of the assumptions of VBT is that the number of empty orbitals in the METAL ION for making bonds with the ligands is equal to its CN. A TRIGONAL bipyramidal GEOMETRY has a hybridisation of sp^3d and hence a CN=5.



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