1.

How many Faraday are required to reduce 1 mole of Cr_(2)O_(7)^(2-) to Cr^(3+) in acid solutions ?

Answer»

2
3
5
6

Solution :(d) The reduction reaction in the acidic medium is :
`Cr_(2)O_(7)^(2-)+14H^(+)+6E^(-) to 2Cr^(3+)+7H_(2)O`
Thus, six Faraday of charge is REQUIRED.


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