1.

How many faradays are required to reduce 1 mole of Cr_(2)O_(7)^(2-) " to "Cr^(3+) in acid medium ?

Answer»

2
3
5
6

Solution :In acidic medium,
`Cr_(2)O^(7)^(2-) + 14 H^(+) + 6e^(-) rarr 2 Cr^(3+) + 7H_(2)O`
Thus, n=6
Hence 6 F CHARGE is reuqired to reduce 1 moel of `Cr_(2)O_(7)""^(2-) ` to `Cr^(3+)` is acidic medium.


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