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| 1. |
How many faradays/coulombs are required to produce (i) 20.0 g of calcium from molten CaCl_(2)? (ii) 40.0 g of aluminium from molten Al_(2)O_(3)? |
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Answer» (ii) `Al_(2)O_(3)to underset(2AL)underset(darr+6e^(-))(2Al^(3+))+underset((3)/(2)O_(2))underset(darr-6e^(-))(3O^(2-))` |
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