1.

How many faradays of charge is transferedduring disproportionation of two moles of cuprous ?

Answer»


Solution :`Cu^(+1) to Cu^(0) + Cu^(+2)` (reduction ) , CHARGE = ` 1e^(-)`
`:.` For 1 mole of cu = 2F , For 2 MOLES of Cu = 1F


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