1.

How many gm. of ethanol is required in the reaction with Na metal in order to give 560 ml. dihydrogen gas at STP ? [mole. mass of ethanol = 46 gm mol^(-1)]

Answer»

1.15
2.3
4.6
11.5

Solution :`underset("(?)")(underset(46 "gram")(C_(2)H_(5)OH))+Na to C_(2)H_(5)ONA + underset(560)(underset(11200 "mili")((1)/(2)H_(2)))`
`(560 XX 46)/(11200)= 2.3` gram Na is NEEDED.


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