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How many gram equivalents of NaOH are required to neutralize `25 cm^(3)` of decinormal HCl solution ?A. `0.00125`B. `0.0025`C. `0.0050`D. `0.025` |
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Answer» Correct Answer - B For acid-base reactions , g-equivalent of acid (HCL) = g-equivalent of base (NaOH) `therefore` g-equivalent of acid = `(25 xx 10^(-3)) dm^(3) xx (1)/(10)` =` 25 xx 10^(-4)` or = 0.0025 = g-equivalent of NaOH |
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