How many gram ions of SO42 are present in 1.25 mole of K2SO4. Al2(SOA)

1.	How many gram ions of SO42 are present in 1.25 mole of K2SO4. Al2(SOA)s. 24H20
Answer» K2SO4. Al2(SO4) 3.24H2O is commonly known as potash alum. In one one complex molecule of potash alum, 4 ions of SO4^2- are present. So in 1.25 moles of potash alum, 4 * 1.25 moles of SO4^2- are present i.e. 5 moles 1 mole of sulphate ions = 96 gm Therefore 5 moles = 96 * 5 gm = 480 gms

How many gram ions of SO42 are present in 1.25 mole of K2SO4. Al2(SOA)s. 24H20

Answer»

K2SO4. Al2(SO4) 3.24H2O is commonly known as potash alum.

In one one complex molecule of potash alum, 4 ions of SO4^2- are present.

So in 1.25 moles of potash alum, 4 * 1.25 moles of SO4^2- are present i.e. 5 moles

1 mole of sulphate ions = 96 gm

Therefore 5 moles = 96 * 5 gm = 480 gms