1.

How many grams of CH_(3)OH should be added to water to prepare 150 ml solution of 2.0 M CH_(3)OH ?

Answer»

9.6
2.4
`9.6xx10^(3)`
`2.4xx10^(3)`

Solution :MOLARITY `=("Wt. of " CH_(3)OH xx 1000)/("Mol. Wt." xx "VOLUME")`
`2.0=("Wt. of " CH_(3)OH xx 1000)/(32xx150)`
`:.` Wt. of `CH_(3)OH=(2.0xx32xx150)/(1000)=9.6 G`


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