1.

How many grams of copper will be replaced in 2L of a 1.50 M CuSO_(4) solution if the latter is made to react with 27.0 of aluminium (Cu=63.5, AI= 27.0)

Answer»

`190.50g`
`95.25g`
`31.75g`
`10.65g`

SOLUTION :2 L of 1.5 M `CuSO_(4)=3` MOL of `CuSO_(4)`
`underset("2 mol")(2Al)+underset("3 mol")(3CuSO_(4))to Al_(2)(SO_(4))_(3)+underset("3 mol")(3 CU)`
2 mol of Al = 3 mol of Cu
(27g = 1 mol of Al)
`=(3)/(2)xx6.3g` of Cu = 95.25 g


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