InterviewSolution
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InterviewSolution
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How many grams of ethylene glycol(molar mass 982) should be addedto 10 kg al water so that theresulting solution freezes at -10%.TCK, for water =1.86K mal, freezingpoint of water = 0°C) |
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Answer» 658g in this answer key of success 658 is the correct answer bhaiya can you answer my question also Ethylene glycol is termed as the primary ingredients in antifreeze.The ethylene glycol molecular formula is C₂H₆O₂.Molar mass of C₂H₆O₂ is = (2×12) +(6×1) + (216) = 62g/molNow that antifreeze by mass is 50%, then there is 1kg of ethylene glycol which is present in 1kg of water.ΔTf = Kf×mΔTf = depression in the freezing point.= freezing point of water freezing point of the solution= O°c - Tf= -TfKf = depression in freezing constant of water = 1.86°C/mM is the molarity of the solution.=(mass/molar mass) mass of solvent in kg=1000g/62 (g/mol) /1kg=16.13mIf we plug the value we get-Tf = 1.86× 16.13 = 30Tf = -30°c |
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