1.

How many grams of Na_(2)CO_(3) should be dissolved in 250 g of water to prepare 0.1 m solution?

Answer»


Solution :`"0.1 m solution MEANS 0.1 mole of "Na_(2)CO_(3)" is present in 1000 g of WATER"`
`therefore " 250 g of water should contain "Na_(2)CO_(3)=(0.1)/(4)"Mole = 0.025 mole "=0.025xx106 g = 2.65 g`


Discussion

No Comment Found