1.

How many grams of NaOH are equivalent to 100 ml of 0.1 N oxalic acid

Answer»

0.2
2
0.4
4

Solution :`N=(W_(B)xx1000)/("EQ. WT."xxV),W_(B)=(Nxx"Eq. wt"xxV)/(1000)`
`=(0.1xx40xx100)/(1000)=0.4`


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