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How many grams of NaOH should be dissolved to make 100 cm^(3) of 0.15 M NaOH solution? |
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Answer» SOLUTION :`1000cm^(3)` of 0.15 M NaOH cotain NaOH = 0.15 mole `therefore""100cm^(3)" of 0.15 M NaOH cotain NaOH"=(0.15)/(1000)xx100=0.015" mole"=0.015xx40g=0.6g` `""("Molar mass NaOH = 40 g mol"^(-1))` |
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