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How many grams of phosphoric acid would be needed to neutralise `100 g` of magnesium hydroxide? (The molecular weight are: `H_(3)PO_(4) = 98` and `Mg(OH)_(2) = 58.3)`A. `66.7 g`B. `252 g`C. `112 g`D. `168 g` |
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Answer» Correct Answer - C Meq. of `H_(3)PO_(4)=`Meq. of `Mg(OH)_(2)` `:.` Meq. of `Mg(OH)_(2)=(100)/(58.3//2)xx100` `=3430.53` `(H_(3)P_(4)`is tribasic acid) `:. (w)/(98//3)xx1000=3430.53` `:. w=112g` |
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