1.

How many `H-` atoms are present in `0.046 g` of ethanol ?A. `6 xx 10^(20)`B. `1.2 xx 10^(21)`C. `3 xx 10^(21)`D. `3.6xx 10^(21)`

Answer» Correct Answer - D
`Mol. Wt. `of `C_(2)H_(5)OH`
`=2xx12+5+16+1=64`
`:. 48g C_(2)H_(5)OH` has `H atm =6xxN_(A)`
`:. 0.046g C_(2)H_(5)OH ` has `H atm`
`=(6xx6.02xx10^(23)xx0.046)/(46)=3.6xx10^(21)`


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