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How many hours does it take to reduce 3 mol of Fe^(3+) to Fe^(2+) with 2.00 A current (1 Faraday=96,500 C mol^(-1),R=8.314JK^(-1)mol^(-1)).

Answer»


SOLUTION :`Fe^(3+)+e^(-)toFe^(2+)` i.e., 1 mol requires 1F. `therefore3` moles will require=3F=`3xx96500C`
`t=Q//I=(3xx96500)//2.0=144750s=40.2`HRS.


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