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How many how many law of exponents there are with e,ample |
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Answer» Answer: am x an = a ( m + n ) Examples : i) 33 x 3 2 = 3(3 + 2) = 35[exponents are added] ii) b5 x b-2 = b5 +(-2)[exponents are added] = b5-2 = b3 (iii) (-6)3 x (-6)2 = (-6)3+2 = (-6)5 (iv) 810 x 812 = 810+12 = 822 Dividing powers with the same base If the bases are same and there is a division between them then, subtract the 2nd exponent from the 1st keeping the base common. am÷ an = a ( m - n ) Examples : (i) 45/ 43 = (4 x 4 x 4 x 4 x 4)/(4 x 4 x 4) = 4( 5 – 3) = 42 (ii) P6÷p2 = p6 - 2 = p4 (iii) 815/812 = 815-12 = 83 (iv) 156/158 = 156-8 = 15-2 (v)(5/2)9 ÷ (5/2)4 = (5/2)9-4 = (5/2)5 Power of a power 3) If there are double exponents then, multiply the exponents and keep the base same. ( am) n = a(m x n ) = amn Examples : (i) (23)2 = 2( 3 x 2 ) [ multiply the TWO powers] = 26 (ii)(-84)2 = (-8)(4 x 2) [multiply the two powers] = (-8)8 (iii) (y-2)-3 = y(-2 x -3) = y6 [ negative times negative --->positive] Zero Exponent 4) Any number with exponent zero ,the answer is 1. a 0 = 1 Example : (i) (1000)0 = 1 (ii) a0 = 1 (iii) (-25)0 = 1 Exponent 1 5) If the exponent is 1 then the number itself is the answer. a1 = a Example : (i) 201 = 20 (ii) b1 = b (iii) (2000)1 = 2000 Negative Exponent 6) If the exponent is negative so to make it positive write the reciprocal of it. a-m = 1/am1/a-m = am Example : i) 4 -2 = 1 / 4 2 = 1 / 16 2) 1 / 3-2 = 3 2 7) Two different bases have same exponents then bring the two bases under common parenthesis and keep the same exponent. am x bm = (ab)mam ÷ bm = (a/ b)m Example 1 : (i) 22 x 32 = ( 2 x 3 )2 = 62 = 6 x 6 = 36 (ii) 62 ÷ 32 = ( 6/3)2 = 22 = 2 x 2 = 4 (iii) 34 x 3-3 = 34 ÷ 33 = 34 / 33 = 81 / 27 =3 hope this helps you |
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