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How many ions are produced from the complex, Co(NH_(3))_(6)Cl_(2) in solution ? |
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Answer» Solution :COORDINATION number of cobalt =6. HENCE, the complex is `[Co(NH_(3))_(6)]Cl_(2)`. It ionizes in the solution as : `[Co(NH_(3))_(6)]Cl_(2)overset(+aq)rarr[Co(NH_(3))_(6)]^(2+)+2Cl^(-)` Thus, THREE ions are produced. |
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