1.

How many ions are produced from the complex Co(NH_(3))_(6)Cl_(2) in solution ?

Answer»

6
4
3
2

Solution :Coordination number of COBALT = 6. Hence, the COMPLEX is [Co(NH3)6]Cl2. It IONISES in the solution as : `[Co(NH_(3))_(6)]Cl_(2) to [Co(NH_(3))_(6)]^(2+) + 2Cl^(-)`. Thus, THREE ions are produced. Option (iii) is correct.


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