1.

How many isomers of the complex Pt(NH_3)_2(SCN)_2 are possible ?

Answer»


SOLUTION :`[Pt(NH_3)_2(SCN)_2]` - cis and trans ISOMERS = 2
`[Pt(NH_3)_2(NCS)(SCN)]` - cis and trans isomers = 2
`[Pt(NH_3)_2(NCS)_2]` - cis and trans isomers = 2
The COMPLEX is square planar , so it does not have a PARI of enantiomer on account of the presence of plane of symmetry.


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