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How many isomers of the complex Pt(NH_3)_2(SCN)_2 are possible ? |
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Answer» `[Pt(NH_3)_2(NCS)(SCN)]` - cis and trans isomers = 2 `[Pt(NH_3)_2(NCS)_2]` - cis and trans isomers = 2 The COMPLEX is square planar , so it does not have a PARI of enantiomer on account of the presence of plane of symmetry. |
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