1.

How many litre of C_(7)H_(16) will be required to react with 176 gm of oxygen. If density of C_(7)H_(16) will be required to react with 176 gm of oxygen. If density of C^(7)H_(16) is 0.8 gm/L?

Answer»

62.5L
40L
50L
80L

Solution :`C_(7)H_(16)+11O_(2)rarr7CO_(2)+8H_(2)O`
`(176)/(32)=5.5`
`n_(C_(7)H_(15))"required"=(n_(O_(2)))/(11)=(5.5)/(11)=0.5`
`d_(C_(7)H_(16))=(50)/(V LIT)0.8rArrV=(50)/(0.8)=(500)/(8)=62.5` litre


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