1.

How many mL of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 of Copper (II) carbonate ?

Answer»

Solution :`8.09 ML ~~ 8 mL`
`underset("1 mol")(CuCO_(3)) + underset("1 mol")(H_(2)SO_(4)) rarr CuSO_(4) + H_(2)O + CO_(2)`
Let of volume of 0.5 M `H_(2)SO_(4)` be V
Moles of `CuCO_(3)-= "Moles of" H_(2) SO_(4)`
`(0.5)/(123.5) = (0.5 xx V)/(1000)`
`therefore""V = 8.09 mL ~~ 8 mL`


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