1.

How many moles of acetic anhydride will be required to form glucose pentaacetate from 2 M of glucose ?

Answer»

2
5
10
`2*5`

Solution :When ecetylated with acetic ANHYDRIDE `(-O-overset(O)overset(||)(C)-CH_(3))`, glucose forms a pentaacetate. The reaction is as follows :

In the GIVEN reaction, 1 M of glucose is producing glucose pentaacetate i.e., it contains 5 OAC group. HENCE, 5 MOLES of acetic anhydride will be required to form from glucose pentaacetate from 2 M of glucose.


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