1.

How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide

Answer»

1
2
3
4

Solution :Iodine is LIBERATED from POTASSIUM iodide.
`{:(K_(2)Cr_(2)O_(7)+4H_(2)SO_(4)rarrK_(2)SO_(4)+Cr(SO_(4))_(3)+4H_(2)O+3[O]),([2KI+H_(2)SO_(4)+[O]rarrK_(2)SO_(4)+I_(2)+H_(2)O]xx3),(ulbar(K_(2)Cr_(2)O_(7)+6KI+7H_(2)SO_(4)rarr4K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+7H_(2)O+3I_(3)...)):}`


Discussion

No Comment Found