InterviewSolution
Saved Bookmarks
| 1. |
How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?A. 0.011B. 0.029C. 0.044D. 0.333 |
|
Answer» Correct Answer - B `underset("x mole")(PbO)+underset("2x moles")(2HCl)rarrunderset("x mole")(PbCl_(2))+H_(2)O` `underset("= 0.029 mole")((6.5)/(224)"mole")" "underset("= 0.087 mole")((3.2)/(36.5)"mole")` Thus, 0.029 mole of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl. |
|