1.

How many moles of magnesium phosphate, Mg_3(PO_4)_2 , will contain 0.25 mole of oxygen atoms ?

Answer»

`3.125 xx 10^(-2)`
`1.25 xx 10^(-2)`
`2.5 xx 10^(-2)`
`0.02 `

Solution :From the molecular formula of `Mg_3(PO_4)_2` .it is CLEAR that 1 mole of `Mg_3(PO_4)_2` CONTAINS 8 mole of O atoms .
8 mole of O atoms = 1 mole of `Mg_3 (PO_4)_2 ` 0.25 mole of O atoms` = 1/8 xx 0.25 `mole of `Mg_3 (PO_4)_2 = 3.125 xx 10^(-2)`


Discussion

No Comment Found

Related InterviewSolutions