1.

How many moles of magnesium phosphate, Mg_(3)(PO_(4))_(2), will contains 0.25 mole ofoxygen atoms?

Answer»

0.02
`3.125xx10^(-2)`
`1.25xx10^(-2)`
`2.5xx10^(-2)`

Solution :`because` 8 MOLE oxygen atoms are PRESENT in 1 mole `Mg_(3)(PO_(4))_(2)`
`therefore` 0.25 mole oxygen atoms will be present in `(1)/(8)xx0.25` mole
`Mg_(3)(PO_(4))_(2)`, i.e.,`3.125xx10^(-2)` mole `Mg_(3)(PO_(4))_(2)`.


Discussion

No Comment Found

Related InterviewSolutions