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How many moles of mercury will be produced by electrolysing 1.0 M Mg(NO_(3))_(2) solution with a current of 2.00 A for 3 hours? [Hg(NO_(3))_(2)=200.6" g "mol^(-1)]

Answer»


Solution :`Hg^(2+)+2E^(-)toHg,Q=2Axx(3xx3600s)=21600C`
`2F=2xx96500C` produce `Hg=1` MOLE
`therefore21600`C will produce Hg `=(1)/(2xx96500)xx21600`mole=0.112 mole


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