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How many moles of methane are required to produce 22 g CO_(2)(g) after combustion? |
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Answer» Solution :The balanced chemical EQUATION for the combustion of methane is : `underset("1 MOLE")(CH_(4))+2O_(2)rarr underset(=12+2xx16=44g)underset("1 mole")(CO_(2))+2H_(2)O` Thus, to produce 44 g `CO_(2), CH_(4)` required = 1 mole `therefore"To produce 22 g of "CO_(2),CH_(4)` required `=(1)/(44)xx22"mole"="0.5 mole"` |
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