1.

How many moles of Na^(+) ions are in 20mL of 0.4 M Na_(3)PO_(4)?

Answer»

0.008
0.024
0.05
0.2

Solution :No. of moles of `Na_(3)PO_(4)=(MV)/(1000)=(0.4xx20)/(1000)`
=0.008
Number of moles of `NA^(+)=3XX` Number of moles of `Na_(3)PO_(4)`.
`=3xx0.008=0.024`.


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