1.

How many moles of `NaOH` are contained in `27 mL` of `0.15 M NaOH`?

Answer» Milli-moles of `NaOH=MxxV_("in"mL)=0.15xx27`
`:.` Moles of `NaOH=(0.15xx27)/(1000)= 4.05xx10^(-3)`


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