Saved Bookmarks
| 1. |
How many moles of `NaOH` are contained in `27 mL` of `0.15 M NaOH`? |
|
Answer» Milli-moles of `NaOH=MxxV_("in"mL)=0.15xx27` `:.` Moles of `NaOH=(0.15xx27)/(1000)= 4.05xx10^(-3)` |
|