1.

How many moles of P_(4)O_(6) and P_(4)O_(10) will be produced by the combustion of 12.4 g of phosphorous (atomic mass 31) in 12.8 g ofoxygen, leaving no P_(4) or O_(2) ?

Answer»

0.1 and 0.3 mol
0.15 mol and 0.25 mol
0.05 mol each
0.1 mol each

Solution :Moles of `P_(4)= (12.4)/(4 xx 31) = 0.1`
Moles of `O_(2)= (12.8)/(32)=0.4`
Let x moles of `P_(4)` from `P_(4)O_(6)` .
Then, moles of `O_(2)` REQUIRED `= x xx 3+(0.1- x) xx 5=0.4`
(given) `implies x = 0.05`


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