1.

How many moles of platinum will be deposited on the cathode when 0.60 F of electricity is passed through a 1.0 M solution of Pt^(4+) ?

Answer»

0.60 mol
0.15 mol
0.30 mol
0.45 mol

Solution :`PT^(4+)(aq)+underset(0.6F)underset(4F)4E^(-) to underset(((1mol)XX(0.6F))/((4F))=0.15" mol")underset(1" mol")(Cu(s))`


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