1.

How many monochloro derivatives are possible when 3-methylheptane is subjected to free radical chlorination?

Answer»


Solution :`overset(1)(C)H_(3)-overset(2)(C)H_(2)-overset(overset(8)(C)H_(3))underset(|)(.^(3)C)H-overset(4)(C)H_(2)-overset(5)(C)H_(2)-overset(6)(C)H_(2)-overset(7)(C)H_(3)`
All the carbon atoms are DIFFERENT and hence EIGHT monochloro derivatives are possible.


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