How many monohaloalkane isomers can be formed on the free radical bromination of (CH3)2CHCH2CH3?(a) 2(b) 3(c) 4(d) 5This question was addressed to me in an online quiz.This intriguing question comes from Methods of Preparation of Haloalkanes topic in chapter Haloalkanes and Haloarenes of Chemistry – Class 12

How many monohaloalkane isomers can be formed on the free radical brom

1.	How many monohaloalkane isomers can be formed on the free radical bromination of (CH3)2CHCH2CH3?(a) 2(b) 3(c) 4(d) 5This question was addressed to me in an online quiz.This intriguing question comes from Methods of Preparation of Haloalkanes topic in chapter Haloalkanes and Haloarenes of Chemistry – Class 12
Answer» The correct choice is (C) 4 Easy explanation: There are four DIFFERENT types of hydrogen atoms that can be REPLACED to give the following four isomers; (CH3)2CHCH2CH2Br, (CH3)2CHCH(Br)CH3, (CH3)2C(Br)CH2CH3 and CH3CH(CH2BR)CH2CH3.

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