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How many number of turns of nichrome wire of specific resistance 10^(-6)Omegam and diameter 2mm that should be wound on a cylinder of diameter 5cm to obtain a resistance of ? |
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Answer» Solution :If R is the radius of the CYLINDER r is the radius of the wire and N is the number of turns `"then"R.=(rhol)/(A)""THEREFORE""R.=(rho(2piR)N)/(pir^(2))` `40=(10^(-6)(2xx2.5xx10^(-2)xxN))/(1XX10^(-6)) therefore N=800` |
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