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How many numbers can be formed from the digits 1, 3, 5, 9 if repetition of digits is not allowed? |
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Answer» To find: number of numbers that can be formed from the digits 1, 3, 5, 9 if repetition of digits is not allowed Forming a 4 digit number:4! Forming a 3 digit number: 4C3 × 3! Forming a 2 digit number: 4C2 × 2! Forming a 1 digit number:4 So total number of ways = 4! + ( 4C3 × 3!) + (4C2 × 2!) + 4 = 24 + 24 + 12 + 4 = 64 |
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