1.

How many numbers of possible stereoisomers are there of 2, 3, 4-trichlo pentanoic acid ?

Answer»

8
12
16
4

Solution :`CH_(3)-overset(.)(C )HCl-overset(.)(C )HCl-overset(.)(C )HCl-COOH`,
i.e., 2,3,4 - trichloropentanoic ACID has THREE dissimilar chiral centres and hence has `2^(3)=8` STEREOISOMERS.


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