1.

How many photons of frequency 10^(14) Hz will make up 19.86 J of energy ?

Answer»

Solution :Total energy emitted per second = Power `xx` time
19.86 J = Power `xx` 1s
`therefore` Power = 19.86 W
Number of photons, `n = (P)/(E) = (P)/(H UPSILON)`
`= (19.86)/(6.6 xx 10^(-34) xx 10^(14)) = 3.009 xx 10^(20)`
`n = 3 xx 10^(20)`
`n_(p) = 3 xx 10^(20)`


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