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How many photons per second emanate from a 50 mW laser of 640 nm ? |
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Answer» Solution :Number of photons emanate per second `n_(p)=P/E=(plambda)/(hc)` P=50mW, `lambda=640nm` `h=6.6xx10^(-34)JS` `c=3xx10^(8)MS^(-1)` `=(50xx10^(3)xx640xx10^(-9))/(6.6xx10^(-34)xx3xx10^(8))=1616.16xx10^(20)` `n_(p)=1.61xx10^(17)s^(-1)` |
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