InterviewSolution
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How many strings can be formed using the letters of the word LOTUS if the word(i) either starts with L or ends with S?(ii) neither starts with L nor ends with S? |
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Answer» (i) To find the number of words starting with L Number of letters in LOTUS = 5 when the first letter is L it can be filled in 1 way only. So the remaining 4 letters can be arranged in 4! =24 ways = n(A). When the last letter is S it can be filled in the 1 way and the remaining 4 letters can be arranged is 4! = 24 ways = n(B) Now the number of words starting with L and ending with S is L OTU S (1) (1) 3! = 6 = n(A ∩ B) Now n(A ∪ B) = n(A) + n(B) – n(A ∩ B) = 24 + 24 – 6 = 42 Now, neither words starts with L nor ends with S = 42 (ii) Number of letters of the word LOTUS = 5. They can be arranged in 5 ! = 120 ways Number of words starting with L and ending with S = 42 So the number of words neither starts with L nor ends with S = 120 – 42 = 78 |
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